(h+2)^2+(-6-1)(h+6)+12=0

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Solution for (h+2)^2+(-6-1)(h+6)+12=0 equation: 



(h+2)^2+(-6-1)(h+6)+12=0

We add all the numbers together, and all the variables

(h+2)^2+(-7)(h+6)+12=0

We multiply parentheses ..

(h+2)^2+(-7h-42)+12=0

We get rid of parentheses

(h+2)^2-7h-42+12=0

We add all the numbers together, and all the variables

-7h+(h+2)^2-30=0

We move all terms containing h to the left, all other terms to the right

-7h+(h+2)^2=30

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